Đáp án:

• \( \int \frac{x}{(x+1)^2} \, dx = \int \frac{x+1 - 1}{(x+1)^2} \, dx = \int \left( \frac{1}{x+1} - \frac{1}{(x+1)^2} \right) dx \)

\( = \ln|x+1| + \frac{1}{x+1} + C \)