Đáp án:

• Đặt \( t = \sqrt{x}\Rightarrow x = t^2 \Rightarrow dx = 2t \, dt \)

• \( I = 2 \int t e^t \, dt \)

   \(= 2 \left[ t e^t - e^t \right] + C \)

   \(= 2 \left[ \sqrt{x} e^{\sqrt{x}} - e^{\sqrt{x}} \right] + C \)