Đáp án:

 - Đường thẳng \(\Delta\) qua \(A(-2, 1, -1)\) có vectơ \(\overrightarrow{a} = (1, 2, 3)\).  
- \(\begin{aligned} \overrightarrow{a} = (1, 2, 3) \\ \overrightarrow{AM} = (4, 2, 2) \end{aligned} \Rightarrow \left[\overrightarrow{a}, \overrightarrow{AM}\right] = (-2, 10, -6). \)  

\( d(M, \Delta) = \frac{\sqrt{4 + 100 + 36}}{\sqrt{1 + 4 + 9}} = \frac{\sqrt{140}}{\sqrt{14}} = \sqrt{10} \Rightarrow \boxed{B} \)